cerebro.run ValueError: invalid literal for int() with base 10

atori

Hi. I'm Japanese boy.
I will try hard to write in English.

I am doing the Adding a Data Feed of quickstart using pandas.
But When cerebro.run, an error of ValueError: invalid literal for int () is issued.

Do you know what is wrong?

Paska Houso

Your datetime in the dataframe seems to be an index.

From the docs (just checked)

https://www.backtrader.com/docu/pandas-datafeed/pandas-datafeed.html

 - The new parameters have the names of the regular fields in the DataSeries and follow these conventions
    - datetime (default: None)
       - None : datetime is the “index” in the Pandas Dataframe

And you are providing a name for datetime. It might be that. Let it be None.

atori

Thank you for your reply.

I solved it by deleting this!
datetime='datetime'

bennetcole

The error message invalid literal for int() with base 10 would seem to indicate that you are passing a string that's not an integer to the int() function . In other words it's either empty, or has a character in it other than a digit.

You can solve this error by using Python isdigit() method to check whether the value is number or not. The returns True if all the characters are digits, otherwise False .

if val.isdigit():

The other way to overcome this issue is to wrap your code inside a Python try...except block to handle this error.

Python2.x and Python3.x

Sometimes the difference between Python2.x and Python3.x that leads to this ValueError: invalid literal for int() with base 10 .

With Python2.x , int(str(3/2)) gives you "1". With Python3.x , the same gives you ("1.5"): ValueError: invalid literal for int() with base 10: "1.5".

nsananguly

@atori Can you suggest what did you do to correct the error ?
I am also facing the same error.

Error that I get is :
ValueError -> 14 cerebro.run()

ValueError: invalid literal for int() with base 10: '28-0'

Seeking guidance on what has gone wrong and how can this be course corrected .